Molar Mass of Ammonia

NH3 — 17.031 g/mol, worked out element by element.

Molar mass of Ammonia, NH₃

17.031 g/mol

Molecular weight 17.031 · 4 atoms per formula unit

Also known as: nh3, azane.

The Haber process product that underpins synthetic fertiliser, and a standard weak-base example.

How 17.031 g/mol is worked out

Mass contribution of each element
ElementAtomsAtomic massMass% of total
Nitrogen114.00714.00782.24%
Hydrogen31.0083.02417.76%
Total417.031100%

M = 1 × 14.007 + 3 × 1.008 = 17.031 g/mol

Grams to moles for Ammonia

Mass to moles conversions
MassMolesFormula units
1 g0.0587 mol3.536 × 10^22
10 g0.5872 mol3.536 × 10^23
25 g1.4679 mol8.840 × 10^23
50 g2.9358 mol1.768 × 10^24
100 g5.8716 mol3.536 × 10^24
250 g14.6791 mol8.840 × 10^24
17.031 g1 mol6.022 × 10^23

For any other amount, use the molar mass calculator, or the molarity calculator to make up a solution of a given concentration.

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Frequently Asked Questions

What is the molar mass of Ammonia?

The molar mass of Ammonia (NH3) is 17.031 g/mol. That is the sum of the standard atomic weights of all 4 atoms in one formula unit: 1 × 14.007 + 3 × 1.008 = 17.031.

What is the molecular weight of Ammonia?

17.031 — the same number as the molar mass, but as a dimensionless ratio rather than in g/mol. The two terms describe the same arithmetic, so a molecular weight of 17.03 and a molar mass of 17.03 g/mol are the same answer.

How many moles are in 100 g of Ammonia?

100 ÷ 17.031 = 5.8716 mol. To convert any mass to moles, divide by the molar mass; to go the other way, multiply.

What is the percent composition of Ammonia?

By mass, Ammonia is 82.24% nitrogen, 17.76% hydrogen. Each element's share is its total mass in the formula divided by 17.031.

How many atoms are in one formula unit of Ammonia?

4: 1 nitrogen, 3 hydrogen. One mole contains 6.02214076 × 10²³ formula units, so a mole of Ammonia contains 4 × 6.022 × 10²³ atoms in total.