Molar Mass of Ammonia
NH3 — 17.031 g/mol, worked out element by element.
Molar mass of Ammonia, NH₃
17.031 g/mol
Molecular weight 17.031 · 4 atoms per formula unit
Also known as: nh3, azane.
The Haber process product that underpins synthetic fertiliser, and a standard weak-base example.
How 17.031 g/mol is worked out
| Element | Atoms | Atomic mass | Mass | % of total |
|---|---|---|---|---|
| Nitrogen | 1 | 14.007 | 14.007 | 82.24% |
| Hydrogen | 3 | 1.008 | 3.024 | 17.76% |
| Total | 4 | 17.031 | 100% |
M = 1 × 14.007 + 3 × 1.008 = 17.031 g/mol
Grams to moles for Ammonia
| Mass | Moles | Formula units |
|---|---|---|
| 1 g | 0.0587 mol | 3.536 × 10^22 |
| 10 g | 0.5872 mol | 3.536 × 10^23 |
| 25 g | 1.4679 mol | 8.840 × 10^23 |
| 50 g | 2.9358 mol | 1.768 × 10^24 |
| 100 g | 5.8716 mol | 3.536 × 10^24 |
| 250 g | 14.6791 mol | 8.840 × 10^24 |
| 17.031 g | 1 mol | 6.022 × 10^23 |
For any other amount, use the molar mass calculator, or the molarity calculator to make up a solution of a given concentration.
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Frequently Asked Questions
What is the molar mass of Ammonia?
The molar mass of Ammonia (NH3) is 17.031 g/mol. That is the sum of the standard atomic weights of all 4 atoms in one formula unit: 1 × 14.007 + 3 × 1.008 = 17.031.
What is the molecular weight of Ammonia?
17.031 — the same number as the molar mass, but as a dimensionless ratio rather than in g/mol. The two terms describe the same arithmetic, so a molecular weight of 17.03 and a molar mass of 17.03 g/mol are the same answer.
How many moles are in 100 g of Ammonia?
100 ÷ 17.031 = 5.8716 mol. To convert any mass to moles, divide by the molar mass; to go the other way, multiply.
What is the percent composition of Ammonia?
By mass, Ammonia is 82.24% nitrogen, 17.76% hydrogen. Each element's share is its total mass in the formula divided by 17.031.
How many atoms are in one formula unit of Ammonia?
4: 1 nitrogen, 3 hydrogen. One mole contains 6.02214076 × 10²³ formula units, so a mole of Ammonia contains 4 × 6.022 × 10²³ atoms in total.