Molar Mass of Iron(II) oxide

FeO — 71.844 g/mol, worked out element by element.

Molar mass of Iron(II) oxide, FeO

71.844 g/mol

Molecular weight 71.844 · 2 atoms per formula unit

Also known as: feo, ferrous oxide.

The other common iron oxide — same elements, different ratio, different name.

How 71.844 g/mol is worked out

Mass contribution of each element
ElementAtomsAtomic massMass% of total
Iron155.84555.84577.73%
Oxygen115.99915.99922.27%
Total271.844100%

M = 1 × 55.845 + 1 × 15.999 = 71.844 g/mol

Grams to moles for Iron(II) oxide

Mass to moles conversions
MassMolesFormula units
1 g0.0139 mol8.382 × 10^21
10 g0.1392 mol8.382 × 10^22
25 g0.3480 mol2.096 × 10^23
50 g0.6960 mol4.191 × 10^23
100 g1.3919 mol8.382 × 10^23
250 g3.4798 mol2.096 × 10^24
71.844 g1 mol6.022 × 10^23

For any other amount, use the molar mass calculator, or the molarity calculator to make up a solution of a given concentration.

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Frequently Asked Questions

What is the molar mass of Iron(II) oxide?

The molar mass of Iron(II) oxide (FeO) is 71.844 g/mol. That is the sum of the standard atomic weights of all 2 atoms in one formula unit: 1 × 55.845 + 1 × 15.999 = 71.844.

What is the molecular weight of Iron(II) oxide?

71.844 — the same number as the molar mass, but as a dimensionless ratio rather than in g/mol. The two terms describe the same arithmetic, so a molecular weight of 71.84 and a molar mass of 71.84 g/mol are the same answer.

How many moles are in 100 g of Iron(II) oxide?

100 ÷ 71.844 = 1.3919 mol. To convert any mass to moles, divide by the molar mass; to go the other way, multiply.

What is the percent composition of Iron(II) oxide?

By mass, Iron(II) oxide is 77.73% iron, 22.27% oxygen. Each element's share is its total mass in the formula divided by 71.844.

How many atoms are in one formula unit of Iron(II) oxide?

2: 1 iron, 1 oxygen. One mole contains 6.02214076 × 10²³ formula units, so a mole of Iron(II) oxide contains 2 × 6.022 × 10²³ atoms in total.