Molar Mass of Manganese(IV) oxide
MnO2 — 86.936 g/mol, worked out element by element.
Molar mass of Manganese(IV) oxide, MnO₂
86.936 g/mol
Molecular weight 86.936 · 3 atoms per formula unit
Also known as: mno2, manganese dioxide.
The catalyst that decomposes hydrogen peroxide, and the cathode of alkaline batteries.
How 86.936 g/mol is worked out
| Element | Atoms | Atomic mass | Mass | % of total |
|---|---|---|---|---|
| Manganese | 1 | 54.938 | 54.938 | 63.19% |
| Oxygen | 2 | 15.999 | 31.998 | 36.81% |
| Total | 3 | 86.936 | 100% |
M = 1 × 54.938 + 2 × 15.999 = 86.936 g/mol
Grams to moles for Manganese(IV) oxide
| Mass | Moles | Formula units |
|---|---|---|
| 1 g | 0.0115 mol | 6.927 × 10^21 |
| 10 g | 0.1150 mol | 6.927 × 10^22 |
| 25 g | 0.2876 mol | 1.732 × 10^23 |
| 50 g | 0.5751 mol | 3.464 × 10^23 |
| 100 g | 1.1503 mol | 6.927 × 10^23 |
| 250 g | 2.8757 mol | 1.732 × 10^24 |
| 86.936 g | 1 mol | 6.022 × 10^23 |
For any other amount, use the molar mass calculator, or the molarity calculator to make up a solution of a given concentration.
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Frequently Asked Questions
What is the molar mass of Manganese(IV) oxide?
The molar mass of Manganese(IV) oxide (MnO2) is 86.936 g/mol. That is the sum of the standard atomic weights of all 3 atoms in one formula unit: 1 × 54.938 + 2 × 15.999 = 86.936.
What is the molecular weight of Manganese(IV) oxide?
86.936 — the same number as the molar mass, but as a dimensionless ratio rather than in g/mol. The two terms describe the same arithmetic, so a molecular weight of 86.94 and a molar mass of 86.94 g/mol are the same answer.
How many moles are in 100 g of Manganese(IV) oxide?
100 ÷ 86.936 = 1.1503 mol. To convert any mass to moles, divide by the molar mass; to go the other way, multiply.
What is the percent composition of Manganese(IV) oxide?
By mass, Manganese(IV) oxide is 63.19% manganese, 36.81% oxygen. Each element's share is its total mass in the formula divided by 86.936.
How many atoms are in one formula unit of Manganese(IV) oxide?
3: 1 manganese, 2 oxygen. One mole contains 6.02214076 × 10²³ formula units, so a mole of Manganese(IV) oxide contains 3 × 6.022 × 10²³ atoms in total.