Molar Mass of Iron(III) chloride
FeCl3 — 162.195 g/mol, worked out element by element.
Molar mass of Iron(III) chloride, FeCl₃
162.195 g/mol
Molecular weight 162.195 · 4 atoms per formula unit
Also known as: fecl3, ferric chloride.
A water-treatment coagulant and a circuit-board etchant.
How 162.195 g/mol is worked out
| Element | Atoms | Atomic mass | Mass | % of total |
|---|---|---|---|---|
| Chlorine | 3 | 35.45 | 106.350 | 65.57% |
| Iron | 1 | 55.845 | 55.845 | 34.43% |
| Total | 4 | 162.195 | 100% |
M = 3 × 35.450 + 1 × 55.845 = 162.195 g/mol
Grams to moles for Iron(III) chloride
| Mass | Moles | Formula units |
|---|---|---|
| 1 g | 0.0062 mol | 3.713 × 10^21 |
| 10 g | 0.0617 mol | 3.713 × 10^22 |
| 25 g | 0.1541 mol | 9.282 × 10^22 |
| 50 g | 0.3083 mol | 1.856 × 10^23 |
| 100 g | 0.6165 mol | 3.713 × 10^23 |
| 250 g | 1.5414 mol | 9.282 × 10^23 |
| 162.195 g | 1 mol | 6.022 × 10^23 |
For any other amount, use the molar mass calculator, or the molarity calculator to make up a solution of a given concentration.
Related compounds
Can't find the exact calculator you need?
Describe it in one sentence — get a working, math-verified calculator in seconds. Free, no signup.
Build your own calculatorRelated Calculators
Frequently Asked Questions
What is the molar mass of Iron(III) chloride?
The molar mass of Iron(III) chloride (FeCl3) is 162.195 g/mol. That is the sum of the standard atomic weights of all 4 atoms in one formula unit: 3 × 35.450 + 1 × 55.845 = 162.195.
What is the molecular weight of Iron(III) chloride?
162.195 — the same number as the molar mass, but as a dimensionless ratio rather than in g/mol. The two terms describe the same arithmetic, so a molecular weight of 162.19 and a molar mass of 162.19 g/mol are the same answer.
How many moles are in 100 g of Iron(III) chloride?
100 ÷ 162.195 = 0.6165 mol. To convert any mass to moles, divide by the molar mass; to go the other way, multiply.
What is the percent composition of Iron(III) chloride?
By mass, Iron(III) chloride is 65.57% chlorine, 34.43% iron. Each element's share is its total mass in the formula divided by 162.195.
How many atoms are in one formula unit of Iron(III) chloride?
4: 3 chlorine, 1 iron. One mole contains 6.02214076 × 10²³ formula units, so a mole of Iron(III) chloride contains 4 × 6.022 × 10²³ atoms in total.