Molar Mass of Lead(II) nitrate
Pb(NO3)2 — 331.208 g/mol, worked out element by element.
Molar mass of Lead(II) nitrate, Pb(NO₃)₂
331.208 g/mol
Molecular weight 331.208 · 9 atoms per formula unit
Also known as: pb(no3)2, lead nitrate.
One of the few soluble lead salts, which is what makes it useful for precipitation reactions.
How 331.208 g/mol is worked out
| Element | Atoms | Atomic mass | Mass | % of total |
|---|---|---|---|---|
| Lead | 1 | 207.2 | 207.200 | 62.56% |
| Oxygen | 6 | 15.999 | 95.994 | 28.98% |
| Nitrogen | 2 | 14.007 | 28.014 | 8.46% |
| Total | 9 | 331.208 | 100% |
M = 1 × 207.200 + 6 × 15.999 + 2 × 14.007 = 331.208 g/mol
Grams to moles for Lead(II) nitrate
| Mass | Moles | Formula units |
|---|---|---|
| 1 g | 0.0030 mol | 1.818 × 10^21 |
| 10 g | 0.0302 mol | 1.818 × 10^22 |
| 25 g | 0.0755 mol | 4.546 × 10^22 |
| 50 g | 0.1510 mol | 9.091 × 10^22 |
| 100 g | 0.3019 mol | 1.818 × 10^23 |
| 250 g | 0.7548 mol | 4.546 × 10^23 |
| 331.208 g | 1 mol | 6.022 × 10^23 |
For any other amount, use the molar mass calculator, or the molarity calculator to make up a solution of a given concentration.
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Frequently Asked Questions
What is the molar mass of Lead(II) nitrate?
The molar mass of Lead(II) nitrate (Pb(NO3)2) is 331.208 g/mol. That is the sum of the standard atomic weights of all 9 atoms in one formula unit: 1 × 207.200 + 6 × 15.999 + 2 × 14.007 = 331.208.
What is the molecular weight of Lead(II) nitrate?
331.208 — the same number as the molar mass, but as a dimensionless ratio rather than in g/mol. The two terms describe the same arithmetic, so a molecular weight of 331.21 and a molar mass of 331.21 g/mol are the same answer.
How many moles are in 100 g of Lead(II) nitrate?
100 ÷ 331.208 = 0.3019 mol. To convert any mass to moles, divide by the molar mass; to go the other way, multiply.
What is the percent composition of Lead(II) nitrate?
By mass, Lead(II) nitrate is 62.56% lead, 28.98% oxygen, 8.46% nitrogen. Each element's share is its total mass in the formula divided by 331.208.
How many atoms are in one formula unit of Lead(II) nitrate?
9: 1 lead, 6 oxygen, 2 nitrogen. One mole contains 6.02214076 × 10²³ formula units, so a mole of Lead(II) nitrate contains 9 × 6.022 × 10²³ atoms in total.